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The hydraulic jump

Energy equation breaks down in a turbulent hydraulic jump so can use conservation of momentum to find the conditions on either side of the jump:

($\displaystyle {\frac{Q^{2}}{g' A_{2}}}$ + A2(h2 - $\displaystyle \hbar_{2}^{}$)) - ($\displaystyle {\frac{Q^{2}}{g'
A_{1}}}$ + A1(h1 - $\displaystyle \hbar_{1}^{}$)) = 0 (5)

\begin{figure}\includegraphics[bbllx=138,bblly=337,bburx=453,bbury=605,height=5in,clip]{../figs/jump_def.ps}\end{figure}

Variable definitions at a hydraulic jump.

\begin{figure}\includegraphics[bbllx=70,bblly=215,bburx=520,bbury=748,height=7in,clip]{../figs/composite.eps}\end{figure}

Hydraulic flow regimes.


Copyright © 2001 by Peter L. Jackson